Alkynes in Organic Chemistry
Alkynes are hydrocarbons containing at least one carbon–carbon triple bond (C≡C). They are unsaturated and belong to the homologous series with general formula CnH2n−2. The simplest alkyne is ethyne (acetylene, C2H2).Contents
Nomenclature
- Common names: Based on acetylene. Example: propyne ≈ methylacetylene.
- IUPAC names: Replace “-ane” with “-yne” in the parent hydrocarbon name.
- Numbering: Number from the end nearer to the triple bond to give it the lowest locant.
- Functional priority: When multiple functionalities exist, apply IUPAC priority rules; the triple bond takes a position number, e.g., but-2-yne.
Structure | IUPAC Name | Common Name |
---|---|---|
HC≡CH | ethyne | acetylene |
CH3–C≡CH | prop-1-yne | methylacetylene (propyne) |
CH3–C≡C–CH3 | but-2-yne | dimethylacetylene |

Structure & Hybridization
Each carbon of the C≡C bond is sp-hybridized (50% s-character), producing a linear geometry (180°). The triple bond comprises one σ bond and two mutually perpendicular π bonds.
Concept tip: More s-character → electrons are held closer to the nucleus → higher acidity of the attached hydrogen (see terminal alkynes below).
Physical Properties
- Generally non-polar; insoluble in water but soluble in non-polar solvents.
- Lower members (C2–C4) are gases; higher members are liquids/solids.
- Burn with a sooty flame due to higher carbon content.
Methods of Preparation
1) Dehydrohalogenation of Dihalides
Vicinal or geminal dihalides give alkynes upon double dehydrohalogenation using alcoholic KOH (first elimination) followed by a strong base like NaNH2 (second elimination).
E.g. CH3–CHBr–CH2Br --(alc. KOH, then NaNH2)--> CH3–C≡CH + 2HBr
2) Hydrolysis of Calcium Carbide
CaC2 + 2H2O → C2H2 + Ca(OH)2
Industrial route to ethyne (acetylene).
Chemical Reactions
Addition Reactions
- Hydrogenation:
- Partial (Lindlar’s catalyst) → cis-alkene.
- Dissolving metal reduction (Na/NH3 (l)) → trans-alkene.
- Complete (excess H2, Pd/C) → alkane.
- Halogenation (X2): One equivalent → dihaloalkene; excess → tetrahaloalkane.
- Hydrohalogenation (HX): Markovnikov addition; excess HX leads to gem-dihalides.
- Hydration (H2SO4/HgSO4): Gives an enol that tautomerizes to a ketone (aldehyde for some terminal cases via anti-Markovnikov with hydroboration–oxidation).
- Ozonolysis: Cleaves the triple bond to yield carboxylic acids (and/or CO2 if terminal).
Acidity of Terminal Alkynes
Terminal alkynes (RC≡C–H) are weakly acidic. Strong bases (e.g., NaNH2, BuLi) deprotonate them to form acetylide anions, which undergo nucleophilic substitution with primary alkyl halides to extend carbon chains.
RC≡C–H + NaNH2 → RC≡C:⁻ Na⁺ + NH3
RC≡C:⁻ + R'–X → RC≡C–R' + X⁻
Uses of Alkynes
- Ethyne + O2 in oxy-acetylene torch → high-temperature flame for welding/cutting.
- Feedstock for solvents, plastics, synthetic fibers, and fine chemicals.
Worked Example: Addition of HCl to Ethyne
HC≡CH + HCl → CH2=CHCl (1 eq.) CH2=CHCl + HCl → CH3–CHCl2 (excess)
Explanation: Stepwise electrophilic addition across the π bonds; Markovnikov orientation in each step forms first vinyl chloride then gem-dichloride.
Practice: MCQ, Fill-ups & Mini-Quiz
MCQ (with answers & explanations)
- The general formula of acyclic alkynes is:
- CnH2n+2
- CnH2n
- CnH2n−2
- CnH2n−6
- The hybridization of carbon atoms in a C≡C bond is:
- sp3
- sp2
- sp
- none
- Selective formation of a cis-alkene from an alkyne uses:
- Na/NH3 (l)
- H2/Lindlar’s catalyst
- HBr (excess)
- O3/H2O
- Terminal alkynes are more acidic than alkenes because:
- They are more polar
- sp carbanion has higher s-character
- They form stronger σ bonds
- Resonance stabilization
- Hydroboration–oxidation of a terminal alkyne generally gives:
- Gem-dihalide
- Aldehyde (via anti-Markovnikov hydration)
- Ketone (Markovnikov)
- Carboxylic acid directly
Fill in the Blanks (answers in [ ])
- In alkynes, each C of the triple bond is [sp] hybridized.
- The flame of burning alkynes is typically [sooty] due to high carbon content.
- Deprotonation of RC≡C–H with NaNH2 gives an [acetylide anion].
- Hydration of a terminal alkyne with H2SO4/HgSO4 yields a vinyl alcohol that tautomerizes to a [ketone].
- Calcium carbide on hydrolysis produces [ethyne].
Mini-Quiz (3 quick questions)
- T/F: Dissolving metal reduction of an alkyne gives a cis-alkene. Show answerFalse. Na/NH3 (l) gives a trans-alkene.
- 1-liner: Name the reagent set that converts 1-butyne → 1,1-dichlorobutane. Show answerExcess HCl (hydrohalogenation, Markovnikov on the formed alkene gives gem-dichloride).
- Predict: Ozonolysis of 2-butyne gives _____. Show answerTwo equivalents of acetic acid (CH3COOH).
FAQs
What is the general formula of alkynes?
CnH2n−2 for acyclic members (n ≥ 2). Why are terminal alkynes acidic?
The conjugate base is stabilized by the high s-character of sp hybrid orbitals holding negative charge closer to the nucleus. How can I differentiate an alkyne from an alkene in the lab?
Alkynes typically decolorize bromine in CCl4; terminal alkynes form precipitates with ammoniacal AgNO3 (silver acetylides). How to get a trans-alkene selectively from an alkyne?
Use dissolving metal conditions (Na/NH3 (l)) for anti-addition.
Internal (CHEMASH)
External (Authoritative)
Quick Revision
- Formula: CnH2n−2
- Hybridization: sp (linear, 180°)
- Key Preps: double dehydrohalogenation; CaC2 hydrolysis
- Selective Partial Hydrogenation: Lindlar (cis), Na/NH3 (trans)
- Terminal Alkyne: weakly acidic → acetylide formation → C–C bond formation