Alkynes in Organic Chemistry: Structure, Preparation, Reactions, and Uses

Alkynes in Organic Chemistry

Alkynes are hydrocarbons containing at least one carbon–carbon triple bond (C≡C). They are unsaturated and belong to the homologous series with general formula CnH2n−2. The simplest alkyne is ethyne (acetylene, C2H2).Contents

Nomenclature

  • Common names: Based on acetylene. Example: propynemethylacetylene.
  • IUPAC names: Replace “-ane” with “-yne” in the parent hydrocarbon name.
  • Numbering: Number from the end nearer to the triple bond to give it the lowest locant.
  • Functional priority: When multiple functionalities exist, apply IUPAC priority rules; the triple bond takes a position number, e.g., but-2-yne.
StructureIUPAC NameCommon Name
HC≡CHethyneacetylene
CH3–C≡CHprop-1-ynemethylacetylene (propyne)
CH3–C≡C–CH3but-2-ynedimethylacetylene
Alkynes in Organic Chemistry
Alkynes in Organic Chemistry

Structure & Hybridization

Each carbon of the C≡C bond is sp-hybridized (50% s-character), producing a linear geometry (180°). The triple bond comprises one σ bond and two mutually perpendicular π bonds.

Concept tip: More s-character → electrons are held closer to the nucleus → higher acidity of the attached hydrogen (see terminal alkynes below).

Physical Properties

  • Generally non-polar; insoluble in water but soluble in non-polar solvents.
  • Lower members (C2–C4) are gases; higher members are liquids/solids.
  • Burn with a sooty flame due to higher carbon content.

Methods of Preparation

1) Dehydrohalogenation of Dihalides

Vicinal or geminal dihalides give alkynes upon double dehydrohalogenation using alcoholic KOH (first elimination) followed by a strong base like NaNH2 (second elimination).

E.g.  CH3–CHBr–CH2Br  --(alc. KOH, then NaNH2)-->  CH3–C≡CH  +  2HBr

2) Hydrolysis of Calcium Carbide

CaC2  +  2H2O  →  C2H2  +  Ca(OH)2

Industrial route to ethyne (acetylene).

Chemical Reactions

Addition Reactions

  • Hydrogenation:
    • Partial (Lindlar’s catalyst) → cis-alkene.
    • Dissolving metal reduction (Na/NH3 (l)) → trans-alkene.
    • Complete (excess H2, Pd/C) → alkane.
  • Halogenation (X2): One equivalent → dihaloalkene; excess → tetrahaloalkane.
  • Hydrohalogenation (HX): Markovnikov addition; excess HX leads to gem-dihalides.
  • Hydration (H2SO4/HgSO4): Gives an enol that tautomerizes to a ketone (aldehyde for some terminal cases via anti-Markovnikov with hydroboration–oxidation).
  • Ozonolysis: Cleaves the triple bond to yield carboxylic acids (and/or CO2 if terminal).

Acidity of Terminal Alkynes

Terminal alkynes (RC≡C–H) are weakly acidic. Strong bases (e.g., NaNH2, BuLi) deprotonate them to form acetylide anions, which undergo nucleophilic substitution with primary alkyl halides to extend carbon chains.

RC≡C–H  +  NaNH2  →  RC≡C:⁻ Na⁺  +  NH3
RC≡C:⁻  +  R'–X  →  RC≡C–R'  +  X⁻

Uses of Alkynes

  • Ethyne + O2 in oxy-acetylene torch → high-temperature flame for welding/cutting.
  • Feedstock for solvents, plastics, synthetic fibers, and fine chemicals.

Worked Example: Addition of HCl to Ethyne

HC≡CH  +  HCl  →  CH2=CHCl   (1 eq.)
CH2=CHCl  +  HCl  →  CH3–CHCl2 (excess) 

Explanation: Stepwise electrophilic addition across the π bonds; Markovnikov orientation in each step forms first vinyl chloride then gem-dichloride.

Practice: MCQ, Fill-ups & Mini-Quiz

MCQ (with answers & explanations)

  1. The general formula of acyclic alkynes is:
    1. CnH2n+2
    2. CnH2n
    3. CnH2n−2
    4. CnH2n−6
    Answer & whyOption (c). Each triple bond reduces two hydrogens compared to alkanes.
  2. The hybridization of carbon atoms in a C≡C bond is:
    1. sp3
    2. sp2
    3. sp
    4. none
    Answer & whyOption (c). One σ + two π bonds require linear sp-hybridized carbons.
  3. Selective formation of a cis-alkene from an alkyne uses:
    1. Na/NH3 (l)
    2. H2/Lindlar’s catalyst
    3. HBr (excess)
    4. O3/H2O
    Answer & whyOption (b). Lindlar’s catalyst gives syn-addition → cis-alkene.
  4. Terminal alkynes are more acidic than alkenes because:
    1. They are more polar
    2. sp carbanion has higher s-character
    3. They form stronger σ bonds
    4. Resonance stabilization
    Answer & whyOption (b). Greater s-character stabilizes negative charge closer to the nucleus.
  5. Hydroboration–oxidation of a terminal alkyne generally gives:
    1. Gem-dihalide
    2. Aldehyde (via anti-Markovnikov hydration)
    3. Ketone (Markovnikov)
    4. Carboxylic acid directly
    Answer & whyOption (b). BH3 addition followed by H2O2/OH⁻ gives an enol → aldehyde.

Fill in the Blanks (answers in [ ])

  1. In alkynes, each C of the triple bond is [sp] hybridized.
  2. The flame of burning alkynes is typically [sooty] due to high carbon content.
  3. Deprotonation of RC≡C–H with NaNH2 gives an [acetylide anion].
  4. Hydration of a terminal alkyne with H2SO4/HgSO4 yields a vinyl alcohol that tautomerizes to a [ketone].
  5. Calcium carbide on hydrolysis produces [ethyne].

Mini-Quiz (3 quick questions)

  1. T/F: Dissolving metal reduction of an alkyne gives a cis-alkene. Show answerFalse. Na/NH3 (l) gives a trans-alkene.
  2. 1-liner: Name the reagent set that converts 1-butyne → 1,1-dichlorobutane. Show answerExcess HCl (hydrohalogenation, Markovnikov on the formed alkene gives gem-dichloride).
  3. Predict: Ozonolysis of 2-butyne gives _____. Show answerTwo equivalents of acetic acid (CH3COOH).

FAQs

What is the general formula of alkynes?

CnH2n−2 for acyclic members (n ≥ 2). Why are terminal alkynes acidic?

The conjugate base is stabilized by the high s-character of sp hybrid orbitals holding negative charge closer to the nucleus. How can I differentiate an alkyne from an alkene in the lab?

Alkynes typically decolorize bromine in CCl4; terminal alkynes form precipitates with ammoniacal AgNO3 (silver acetylides). How to get a trans-alkene selectively from an alkyne?

Use dissolving metal conditions (Na/NH3 (l)) for anti-addition.

Internal (CHEMASH)

External (Authoritative)

Quick Revision

  • Formula: CnH2n−2
  • Hybridization: sp (linear, 180°)
  • Key Preps: double dehydrohalogenation; CaC2 hydrolysis
  • Selective Partial Hydrogenation: Lindlar (cis), Na/NH3 (trans)
  • Terminal Alkyne: weakly acidic → acetylide formation → C–C bond formation

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top